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5 DATA LINK PROCESSING TIME
MELSEC-QnA
(b) For writing
MB = [SM + LS + {(No. of writing points + 16)/72}
1
× LS + α
+ SM + LS × 3 + β + constant bps] × N [ms]
SM : Master station sequence scan time
LS : Link scan time (Refer to section 5.2)
α : Send end internal processing time
LS
β : Receive end internal processing time
LS
[Constant bps]
Transmission speed 156kbps 625kbps 2.5Mbps 5Mbps 10Mbps
constant bps LS LS × 2 LS × 4 LS × 6 LS × 7
N : No. of execution instructions simultaneously
1 : Raise the decimals to a unit
(Example) When master station sequence scan time is 10ms, link scan time is 5ms,
no. of writing points is 20 words, transmission speed is 10Mbps, no. of
execution instructions simultaneously is 1
MB = [SM + LS + {(No. of writing points + 16)/72}
1
× LS + α
+ SM + LS × 3 + β + constant bps] × N
= [10 + 5 + {(20 + 16)/72}
1
× 5 + 5 + 10 + 5 × 3 + 5 + 5 × 7] × 1
= [10 + 5 + 1 × 5 + 5 + 10 + 5 × 3 + 5 + 5 × 7] × 1
= 90 [ms]