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6 F 3 B 0 3 6 4
52
Node 6Node 5Node 4Node 1Node 2Node 3
Network
power-supply
unit
Power
tap
Section 1
120 m
V
+−
1.1A 1.25A 0.5A V
−
0.25A 0.25A 0.85A
Section 2
120 m
Figure 3.14 Example of Overloaded Single Power Unit Central Connection
a) Sum of current consumption in section 1 = 1.1A + 1.25A + 0.5A = 2.85A
a') Sum of current consumption in section 2 = 0.25A + 0.25A + 0.85A = 1.35A
b) Total length extended in section 1 = Total length extended in Section 2 = 120 m
c) Maximum current available on the cable based on Figure 3.10 = approx. 2.56A (Obtain the
approximate value between 100 to 150 meter straight cable.)
d) Since the sum of current consumption in section 1 > maximum current, the current is
overloaded.
Solution: Move the power tap to the overcurrent section. See Figure 3. 15.