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Appendices
January 2009 UDA2182 Universal Dual Analyzer Product Manual 203
Because there are two different types of wire used in each lead to the cell in this example,
the total lead resistance is calculated as follows: (Note: the analyzer accounts for the fact
that there is always a pair of conductor wires in the system loop.)
(0.5 x 6.4) + (0.2 x 10.2) = 5.24 ohms
Since the analyzer only allows entry of one wire gauge type, we allow for the worst-case
condition by dividing the total resistance by the resistance per thousand feet of the higher
resistance gauge wire. In our example this would be:
5.24 ohms
÷ 10.2 ohms per thousand feet of 22 AWG wire = 514 feet
Therefore, in our example we would use the procedure in Table 6-5, and specify the wire
gauge as 20 AWG and the length as 514 feet. (20 AWG wire simulates 22 AWG coax)